Correct answer: Be51...Qc2/Qc3/Qc4[a]/Qc6/Qc8/Qf4+[d] 2.Nf4#[C] 1...Nc3/Qc5+/[б]//Qd2/Qe3[c] 2.Nc5#[A] 1...Rh5/Rh4/Rh3/Rh2/Rh1/
