Correct answer: Ba31...Bb2[a] 2.B:b2#[A] 1...Bc3/[б]/ 2.Q:c3#[Б] 1...N:e4[c] 2.Ne2#[C] 1...Nd3[d] 2.Nf3#[D] 1...Bd7/Re8/Rf8/Rg8/Rh8 2.Q:d6# 1.