Correct answer: Rh51...Rf5[a] 2.N:f5#[Б] 1...Rf7/Bf6/[б]/ 2.N:f7#[D] 1...b5/Bb3/Bc2/Bd1 2.e8N#[A] 1...Rf6 2.Rd4#/Be5#[C] 1...Rf8+ 2.e:f8Q#/e:f8<