Correct answer: Qa81...e6[a]/Be8/B:a4[c] 2.e5#[A] 1...B:g4/[б]//Bc8/c6[d] 2.c5#[Б] 1...Be6 2.Qh8# 1...Bf5 2.e:f5#/c5#[Б] 1...Bb5 2.c:b5#/e5#[A] 1.Q:d7? (2.c5#[Б]/e5#[A])
