Correct answer: Qd51...Bc4[a]/Bd3/[б]//Be2/[б]//Bf1/[б]//Bd7[d] 2.Qd7#[A] 1...Bc6[c] 2.N:a6#[Б] 1...Qa5[e]/Qc8[g] 2.Qc8#[C] 1...Qb7[f] 2.N:b5#[D] 1...<
