Correct answer: Bc51...b:a5[a]/b5 2.Rc5#[A] 1...Qg5/Qg4/Qg3/Qg2/[б]//Qg1/Q:g7/Qd6/Qh7/Qf5/Qf7/Qe8 2.Rd6#[Б] 1.Bd6? (2.Nb4#) 1...b:a5[
