Correct answer: Qe41.Qh1? (2.d6#) 1...Kd6[a] 2.Qh2#[Б] 1...d6/[б]/ 2.Qh7#[C] but 1...Bf3! 1.Qc1+?? 1...Kd6[a] 2.Qc5#/Qf4#[A] but 1...Bc4! 1.Qc2+
