Correct answer: Nd71.Bc7? (2.Qb8#) 1...Re3[a]/Qf3[a] 2.Ne6#[A] 1...Qg3/[б]/ 2.Ng6#[Б] 1...Qh3[c] 2.Nh7#[C] but 1...Re8! 1.Nd7! (2.Qb8#)
