Correct answer: N:b61...Bd7[a] 2.Rf6#[A] 1...Ncd4/[б]//Ne7[c]/Nb4[d]/Nb8[e]/Na7[e] 2.Re7#[Б] 1...Nf4[f]/Ng1/Ng3/Ned4[g]/Nc1 2.N:f4#[C] 1...h4 2.