Correct answer: Rb51...B:d5+ 2.Q:d5# 1...Bc8/Ba6 2.Nc7#[A] 1.Qe8? zz 1...Bc6[a] 2.Q:c6#[Б] 1...Bc8/Ba6/f3/[б]/ 2.Nc7#[A] but 1...B:d5+! 1.Q