Correct answer: Qd21.Qa4? (2.Rg5#) 1...Qh4[a]/Qe4 2.Qe4#[A] 1...Bg6/[б]/ 2.Qd7#[Б] but 1...Bc4! 1.Ncd3? (2.Rg5#) 1...Qh4[a] 2.N:f7#[C] 1...
