Correct answer: Ng51...Nf1/Nf5[a]/Ng2/Nd1 2.Qe5#[A] 1...Nd5 2.Nc8#/Qe5#[A] 1.Qh4? (2.Qe7#[Б]) 1...Nd5 2.Nc8# but 1...Nf5[a]! 1.Qc3? (
