Correct answer: R:d51...Q:f6[a]/Qf8/Qg7/Qh7/Qg6 2.Q:d5# 1...Bc2+/Ba2 2.Q:c2# 1.N:d5? (2.Qc4#) 1...Q:f6[a] 2.N:f6#[Б] 1...Be5/[б]/ 2.