Correct answer: Qc21...Kd1[a]/Nf1/[б]//Nc4/[б]/ 2.Rb1#[A] 1...Nb3[c] 2.Re4#[Б] 1...Ne4/Nf3/Nb1 2.Rb1#[A]/R:e4#[Б] 1.Rb5? zz 1...Kd1[a]/Ne4