Correct answer: Qd61...e4[a] 2.Qc3#[A] 1...c4/[б]/ 2.Bb4#[Б] 1.Bd6? (2.B:c7#) 1...e4[a] 2.Qc3#[A] 1...c4/[б]/ 2.Bb4#[Б] 1...c:d6[c] 2.Qd8#[C] but 1...Rh7! 1.K