Correct answer: Qa31.Nb:d2[A]? (2.Ne4#/Nb1#) 1...N:c4[a]/Nc6/[б]/ 2.Qa3#[Б] but 1...d3! 1.Qa3[Б]! (2.Q:a5#) 1...Nb7/Na:c4[a]/Nc6/[б]/ 2.Nb:d2#[