Correct answer: d31...Nc3[a] 2.Q:c3#[A] 1...Bh2/[б]//Bf2 2.Bf2#[Б] 1...Be3[c] 2.d:e3#[C] 1...e4 2.Bf6# 1...g5 2.Nf5# 1...Nb2/Nb6 2.Qc3#[A]/Q:c5# 1...N<