Correct answer: Qb31...Be3[a] 2.d:e3#[A] 1...d5/[б]/ 2.Qb6#[Б] 1...Nd1[c]/Nd5[d]/Ne2[c]/Ne4[c]/Nb1[c]/Na2[c]/Na4[c] 2.Qe4#[C] 1...Bh2/Bf2+ 2.Bf2# 1...<
