Correct answer: Qb61...d:c3[a] 2.Qd6#[A] 1...B:c3/[б]/ 2.Qf5#[Б] 1.Qf2? (2.Qd2#/Q:d4#) 1...d:c3[a] 2.Nc5#[C] 1...B:c3/[б]/ 2.Qf5#[Б] 1...K:c3 2.Qd2#
