Correct answer: Kc21...e2[a] 2.N3d2#[A] 1...Nc5/[б]//Nd6[c]/Nd8[c]/Na5[c] 2.Na5#[Б] 1...d3[d] 2.Qe4#[C] 1...B:b3 2.B:b5#/Q:b5# 1.N1d2+?? 1...Kc3 2.