Correct answer: Qb11.Qh6? zz 1...d:c3/[б]//d3[c] 2.Qe3#[A] 1...a:b6[d] 2.Qf8#[Б] but 1...K:b6[a]! 1.Qh4? zz 1...d:c3/[б]//d3[c] 2.Qf2#[C] 1...a:b6[d] 2.Qe7#[D] but 1...K