Correct answer: Bf51...Bd5[a] 2.Ng6#[A] 1...Bd4/[б]/ 2.Bf4#[Б] 1...Qf5 2.Q:f5# 1.Qh8?? (2.Qb8#) 1...Qg8[c]/Q:e3[d] 2.Q:f6# but 1...Bc6! 1.Q