Correct answer: Qf41...B:e2 2.N:e2# 1...B:c3 2.Bb6#[A]/Qc5#[Б] 1...Nb1/Nb5+/N:c4 2.Nb5# 1.Ba5? (2.Qc5#[Б]) 1...Nb5+ 2.N:b5# but 1...Nb4!