Correct answer: Bb81...Bh4[a]/Be7[a]/Bd8[a] 2.R:d2#[A] 1...Bf6/[б]/ 2.Ne3#[Б] 1...Ng6 2.B:f7# 1...Rb2/Rb1/Rb5/R:b6/Be3 2.c4# 1...Rb4/Ra3