Correct answer: Kg61...Kf3[a] 2.Qd3#[A] 1.Bf2? zz 1...Kf3[a] 2.Qe3#[C] 1...Ke5/Bf3/[б]/ 2.Qd4#[Б] but 1...Bg2! 1.Bf1?? (2.Qd3#[A]) 1...Kf3[