Correct answer: Nb41...Kc4[a] 2.Qb4#[A] 1...Ke5/[б]/ 2.Qf6#[Б] 1.Nc7? (2.Qc5#) 1...Kc4[a] 2.Bd5#[C] 1...Ke5/[б]/ 2.Qg7#[D] but 1...Ke3! 1.Bf3+
