Correct answer: Nde51...Nf5[a] 2.Ng5#[A] 1...Be5/[б]//Bc7/Bb8 2.N:c5#[Б] 1...e6/e5 2.Nf6# 1.Rdd5? (2.Ng5#[A]/Nd2#[C]) 1...Be5/[б]/ 2.N:c5#[Б]/Nd2
