Correct answer: N:e41...N:d3[a]/Nd7[a]/Ne6/Nb3[a]/Nb7/[б]//Na4[a]/Na6[c] 2.Be6#[A] 1...Nf2[d]/Nc3[e]/Nb2[d] 2.R:e3#[Б] 1...e:d3 2.Bg2# 1.Bc6? z
