Correct answer: Qc51...N:g3/Ng7/Nh4[a]/Nh6/Ne7/Nd6 2.d3# 1...Ne3 2.d:e3# 1...Qe4 2.R:e4# 1.Qc6? (2.Q:f3#) 1...Nh4[a] 2.N:h5#[Б] 1...N
