Correct answer: Qe11...Ke5[a] 2.Nc6#[A] 1...Kc5 2.Na6# 1.Kd2? (2.Nc6#[A]/Nd3#[Б]) 1...Ke5[a]/Bd7/Bf8 2.Nc6#[A] 1...Kc5 2.Nc2#/Na6# bu
