Correct answer: Qf11...Kc4[a] 2.Q:d5#[A] 1...d:e4/[б]/ 2.Q:e4#[Б] 1.Rb2?? (2.Bb5#/Q:d5#[A]) 1...Kc4[a] 2.Q:d5#[A] 1...c2 2.Bb5# 1...d4 2.Bb5#/Qb5# bu
