Correct answer: Kf21...Qa3[a]/Qb4[a]/Qc2[a]/Q:b5[a] 2.Nc2#[A] 1...Qc4 2.Nf5# 1...Qb3 2.N:b3# 1...c4 2.B:b6# 1...e4 2.Bf6# 1.Bg5[Б]? zz 1...Qa
