Correct answer: Rd41...e2[a] 2.Bd4#[A] 1...f6/[б]//f5[c] 2.Q:e6#[Б] 1...Nc2[d]/Nc6[d]/Nd3[e]/Nd5[f]/Na2[e]/Na6[e] 2.Nd3#[C] 1...Nh1/Nh5/Nf1/Nf5/Ne
