Correct answer: Nc41...Nc3[a] 2.Nc5#[A] 1...Bg4/Bh5/Be4/[б]/ 2.Qe4#[C] 1...N:d2 2.R:d2#[Б] 1.Rcc2?? (2.Nc5#[A]) 1...Be4/[б]/ 2.Q:e4#[C] but 1...N