Correct answer: Rd71...Nf6[a] 2.Bf5#[A] 1...Nd6/[б]/ 2.Bd5#[Б] 1.Rf7? (2.Bf5#[A]) 1...Nf6[a] 2.Re7#[C] 1...Nd6/[б]/ 2.Bd5#[Б] but 1...Ng7! 1.B
