Correct answer: Qa41...e5[a] 2.Kc4#[A] 1...c5/[б]/ 2.Ke4#[Б] 1.Qg4? (2.Qd4#) 1...e5[a] 2.Ne4#[D] 1...Kd7/c5/[б]/ 2.Q:e6#[E] 1...Ke5 2.Qf4# but 1...Kc5!
