Correct answer: Ne61...B:d3[a] 2.B:d3#[A] 1...Ne5/[б]//Nb4[d]/Nb8[d]/Na5[d]/Na7[d] 2.R:e5#[C] 1...Ne7[c] 2.Qf6#[D] 1...f6 2.Be6#[Б] 1...Qb6/Qb5/Q