Correct answer: Qe81...d6[a] 2.Ne7#[A] 1...Ne4/[б]/ 2.Qb3#[Б] 1...Ne6[c] 2.Qf3#[C] 1.B:f6? (2.Qe5#) 1...d6[a] 2.Ne7#[A] 1...Ne4/[б]/ 2.Qb3#[Б] but 1...N
