Correct answer: Nc21.Nf5? (2.Qd4#[A]) 1...Kd3[a]/Kd2/[б]/ 2.Qe3#[Б] but 1...e5! 1.Qd6?? (2.Ne2#/Ne4#) but 1...e:d6! 1.Nc2! (2.Qe3#[Б]) 1...Kd2/[б]/ 2