Correct answer: Qb71...Kf1/Bg4/B:f5 2.Qh1# 1...Bf1 2.Qd2# 1.Qd3? (2.Qe2#[A]/Qb1#[Б]) 1...Bf1 2.Qd2#/Qb1#[Б] 1...B:f5 2.Qe2#[A] but 1.
