Correct answer: N:d51...Kc3[a] 2.Qe3#[A] 1...e5/[б]/ 2.Qd2#[Б] 1.Bh6? zz 1...Kc3[a] 2.Qd2#[Б] 1...e5/[б]/ 2.Qe3#[A] but 1...Kc5! 1.R:e6?? (2.Qd2#[Б]) 1