Correct answer: N:c61...Ke4[a] 2.B:c2#[A] 1...Ke6/[б]/ 2.Qf6#[Б] 1...Nf1[c]/Nc4[d] 2.B:g4#[C] 1...Bf6[e]/Bd6[f] 2.Q:g6#[D] 1.B:c2+[A]?? 1...Ke6/[б]/ 2
