Correct answer: Qf51...B:d4[a] 2.Nb4#[A] 1...Nc6/[б]/ 2.Nc3#[Б] 1...Nb5[c] 2.Qc4# 1...Nce6/Ne8/Na6[d]/Na8 2.Nc3#[Б]/Qc4# 1...b5 2.Rc5# 1...Nde