Correct answer: Bd21...Rd4/Be3+[a]/Ba5 2.Ne3#[A] 1...Rg3/Rf1/Re1/R:d1/Rh1 2.Q:g3# 1...B:f2 2.N:f2# 1.Bc5[Б]? (2.Nd6#[C]/Ne3#[A]) 1.
