Correct answer: Qa51...Bh2/Be3 2.Ne3# 1...Nb4 2.Qc3#/Q:b4# 1...Nc3+ 2.Q:c3# 1...Rd2/R:e1 2.N:d2# 1.Qe3? (2.Nb6#[A]) 1...Nc3+ 2.Q: