Correct answer: Qc71...Nc4[a] 2.Qe4#[A] 1...Nc6/[б]/ 2.Q:b3#[Б] 1...N:d4[c] 2.Nc7#[C] 1...Nc1/Nc5/Nd2/Na1 2.Qc5# 1.K:f7? zz 1...Nc4[a] 2.Q