Correct answer: Nb31...Rc3[a] 2.Rd2#[A] 1...Rc2/[б]/ 2.Be2#[Б] 1...Qh2/Qh4 2.Qg6# 1...Qh1 2.Bg4#/Bh5#/Bd1#/Bd5#/B:c6#/Qg6# 1...Qh5+ 2.