Correct answer: Nd31...Qf2[a]/Q:c3/Be2/Ne3 2.Nd6#[Б] 1...B:c3/[б]//Ba5 2.R:c5#[C] 1...Q:e4+ 2.Q:e4# 1...Qf1/Qg1/Qh1/Qg3/Qh4 2.Nd2#[A
