Correct answer: Nbd41...Qh3[a]/Qg5[a]/Qf4/Qc1 2.Nd6#[A] 1...Qg6/Qf6/[б]//Qe6/Qc6/Qa6 2.Ne3#[Б] 1...Qh5/Qh4/Qh2/Qh1/Qh7/Qh8/Q