Correct answer: Kb51...d6[a] 2.Qf5#[A] 1...d5/[б]/ 2.Nc5#[Б] 1.g6? (2.Qe5#[C]) 1...d6[a] 2.Qf5#[A] 1...d5/[б]/ 2.Nc5#[Б] but 1...Kd5[c]! 1.Kb3? zz 1...d6[a] 2.Qf5#[A